case in bash script

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javiermarcon : 30/09/03 02:45 PM : Incident created -   Hello I made a bash script, with a ccase, but it doesn't select the '? )' option. Here is the script: #!/bin/bash case $1 in 'pepe' ) valor='10k' valor2='15k' ;; 'pepa' ) valor='12k' valor2='17k' ;; 'pepeon' ) valor='20k' valor2='25k' ;; ? ) echo 'Hay que elegir algo' exit 0 esac echo '$1 $valor $valor2' The problem is that it never gives me the error echo 'Hay que elegir algo', if i don't put any of the values that the case have. How can i fix it to give me that echo message when I put an opion that is not pepe, pepa or pepon? Thanks.
nexus_la : 06/10/03 07:41 PM : More info requested -   Try this variant(replace ? with *): #!/bin/bash ... valor='20k' valor2='25k' ;; * ) echo 'Hay que elegir algo' exit 0 ...
javiermarcon : 08/10/03 03:23 PM : Incident closed -

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